![]() In the end, my shebang looks like #!/usr/bin/pil -argv dummy len bind the first argument (path to script) to dummy second argument to len len isn't actually going to be loaded because (bye) has been called before its loading starts. This means I can't pass another "-" argument to pil Use the RANDOM variable with cut command to generate random string in Bash. Creating Random Numbers and Strings in Bash is fairly simple. The problem is, it can only pass one argument: everything after the space in the shebang is passed to the program as $1 in shell notation. Our online random password generator is one possible tool for generating strong passphrases. If the file exists previously, it will retrieve its contents, behaving just like withfile. The shebang tells the kernel to pass this file to the specified program, like #!/bin/bash It can also pass an argument to the program, for instance, #!/usr/bin/pulseaudio -nF in some PulseAudio config files. Generates a random plaintext password and stores it in a file at a given filepath. There's just one problem: I have to write this command in the shebang. This would've been the solution: pil -"argv dummy dummy len" random-string - 60 would bind dummy to "random-string", then to "-", then len to "60", after which it'll load my script where len is available. If pil sees an argument that's just a "-", it'll stop loading subsequent arguments as files. For example, -bye runs (bye) immediately, exiting the program -argv dummy len runs (argv dummy len) which binds the first command line argument to dummy and second to len but those arguments are still going to be loaded as files. I am attaching a screenshot of hits that came up for me in response to the above search string. ![]() Pil reads command line arguments starting with a "-" as a function to run or, more specifically, as a form to evaluate after wrapping it in parentheses. That seemed unstatisfying to me (I don't know why now that I've realized how hacky this next solution is), so I went with a hack to bind the first command line argument to a variable in the script. There are two ways around this: one is to simply wrap the whole thing into a shell script, and handle arguments there. This becomes a problem when the whole point of the script is to be a shell command. Best way to generate a random string following a specific pattern in Bash Ask Question Asked 11 years, 10 months ago Modified 9 years, 6 months ago Viewed 9k times 7 I'm wanting to generate many six character strings all following this pattern: consonant vowel consonant consonant vowel consonant e.g. The interpreter itself processes arguments as files to load or functions to invoke. In Picolisp, command line arguments can't be accessed directly in the program. ![]() I first saw Picolisp because it is currently (as of 2018-10) the only Lisp family language packaged in Termux.
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